134 RELATION OF PROTEINE TO ALLANTOINE. 



5 (G 48 N 6 H 39 15 ) + 3 = C 240 N 30 H 196 84 

 f 6 at. hippuric acid, 6 (C 18 N H 8 O 6 ) = C 108 N 6 H 48 O 30 



9 at. urea, 9 (C 2 N 2 H 4 O 2 ) = C 18 N 18 H 36 O 18 



= <( 3 at. choleic acid, 3 (C 38 N H 33 O n ) = C 114 N 3 H 99 O 33 



3 at. ammonia, . . 3 ( N H 3 ) = N 3 H 9 

 t'$ at. water, .... 3 ( H O ) = H 3 O 3 



The sum is C 240 N 30 H 196 O 84 



or, 



5 (C 48 N C H 39 1S ) + 46 = C 240 N 30 H 195 120 

 f 6 at. benzoic acid, 6 (C 14 H 5 O 3 ) = C 84 H 30 O 18 



I 27 at. urea, 27 (C NH 2 O ) = C 27 N 27 H M O 27 



= J 3 at. choleic acid, 3 (C 38 NH 33 O U ) = C 114 N 3 H 99 O 33 



15 at. carbonic acid, 15 (C O 2 ) = C 15 O 30 



L12 at. water, ... 12 ( H O )= H 12 O 12 



34. Lastly, let us follow the metamorphosis of the 

 tissues in the foetal calf, considering the proteine furnish- 

 ed in the blood of the mother as the substance which 

 undergoes or has undergone a transformation ; it will 

 appear that 2 at. of proteine, without the addition of 

 oxygen or any other foreign element, except 2 at. of 

 water, contain the elements of 6 at. of allantoine and 1 

 at. of choloidic acid, (meconium ?) 



2. at proteine=2 (C 48 N 6 H 36 O 14 )+2 at. water= 2 HO == C 96 N 12 H 74 O 30 

 _J 6 at. allantoine, 6 (C 4 N 2 H 3 O 3 ) = C 24 N 12 H 18 O 18 

 " \\ at. choloidic acid ( = C 72 H 56 O 12 



C 96 N 12 H 74 30 



35. But the elements of the six atoms of allantoine 

 in the last equation correspond exactly to the elements 

 of 2 at. of uric acid, 2 at. of urea, and 2 at. of water. 



!2 at. uric acid C 20 N 8 H 8 O 12 

 2 at. urea .C 4 N 4 H 8 O 4 

 2 at. water H 2 O 2 



C 24 N 12 H 18 O 18 

 The relations of allantoine, which is found in the 



