270 APPENDIX. 



weight of_ hydrogen = 12-478 ; N a weight of nitrogen 

 = 177-04 ; and lastly, O a weight of oxygen = 100. 



The formula of proteine, C 48 N 6 H 36 O 14 , expresses, there- 

 fore, 



48 times 76-437 = 3668-98 carbon, 

 6 times 177-040 1062-24 nitrogen, 

 36 times 12-478= 449-21 hydrogen, 

 14 times 100-000 = 1400-00 oxygen. 



The sum gives a weight of 6580-43 proteine. 

 Therefore, 



In 100 parts. 



In 6580.43 parts of proteine are contained 3668-98 carbon 55 756 

 In 6580-43 ditto 1062 24 nitrogen 16-142 



In 6580-43 ditto 449-21 hydrogen 6-827 



In 6580-43 ditto 1400-00 oxygen 21-275 



100-000 



The actual results of analysis, reduced to 100 parts, 

 when compared with the above numbers, will show how 

 far the assumed formula is correct ; or, supposing the for- 

 mula ascertained, they will show the degree of accuracy 

 displayed by the experimenter. Thus the proportions in 

 100 parts, calculated from the formula, furnish an impor- 

 tant check to the operator, and, conversely, the formula 

 calculated from his results, when compared with other 

 known formulae, supplies a test of his accuracy, or of the 

 purity of the substance analyzed. 



