12 THE TABLES: EXPLANATORY 



tain if the weight of an individual or group of individuals 

 is normal, proceed as follows : Having ascertained the 

 trunk-length and the chest-circumference, find first in 

 Table I. or Table VII. the weight corresponding to 

 the observed trunk-length, then look up the weight 

 for the observed chest-circumference in Table II. or 

 Table VIII. ; add the two weights together and divide 

 by two, and the normal weight for an individual of 

 the observed trunk-length and chest-circumference will 

 have been obtained. The weight derived from the 

 Tables is now compared with the actual weight observed, 

 and the percentage deviation above or below the normal 

 is readily calculated. The figure derived from the 

 Tables should always be taken as equal to 100 per cent. 

 If the individual represents an average type, the two 

 weights obtained from the two measurements will be 

 found practically identical ; thus : 



EXAMPLE 



FEMALE, AGE 10 YEARS 



C Weight of the body =34-0 kilograms 



Observations j Length of the trunk =72-7 centimetres 



(Circumference of the chest =64-0 centimetres 



CALCULATION 



Weight derived from length of the trunk (72-7 cm.) 



= 34-15 kilos (from Table VII.). 

 Weight derived from circumference of the chest (64-0 cm.) 



= 33-84 kilos (from Table VIII.). 

 Averaging 34-15 + 33-84 = 34<0 knos ^ which . g the normal 



weight corresponding to the observed length of the trunk 



and the circumference of the chest. 

 Subtracting the calculated from the observed weight, 



34-0-34-0 = 0. 



Therefore the person weighs exactly what she should weigh 

 according to the Tables. 



