254 THE ATOMIC WEIGHTS. 



three ratios from which to compute the atomic weight of molybdenum, 



viz : 



(i.) Percentage Mo in MoO 3 , 66.665, =b .0022. 

 (2.) 2AgCl : MoO 3 : : 100 : 50.202, .0018 

 (3.) 2NaCl : Ma. 2 MoO 4 : 56.745, .0017 : 100. 



These involve the following values : 



O = 15.879, .0003 AgCl 142.287, .0037 



Na = 22.881, .0046 NaCl = 58.060,^.0017 



Hence for the atomic weight in question 



From (i) ......................... Mo = 95.267, .0072 



From (2) ......................... " = 95.225, .0064 



From (3) ........................ " 95.357, .0126 



General mean ............... Mo = 95.259, .0045 



With = 16, Mo = 95.985. 



This value is essentially that derived from Seubert and Pollard's data 

 alone. Reducing the latter to a vacuum would affect the result very 

 slightly so slightly that the correction may be ignored. 



