KINDS AND QUANTITIES OF FEED 77 



89. The nutritive ratio of any feed is the ratio of its 

 protein to its carbohydrates. 



90. Rule. To find the nutritive ratio of two or more differ- 

 ent feeds when fed in combination, take the sum of the pro- 

 tein in the combined feeds as the antecedent of a ratio in 

 which the sum of the carbohydrates is the consequent, and 

 reduce the ratio to its lowest terms. 



EXAMPLE. What is the nutritive ratio of a ration consisting of 

 10 Ib. of corn, 31b. of cottonseed meal, and 15 Ib. of timothy hay ? 



SOLUTION. From the table it is seen that 7.8 Ib. of every 100 Ib. 

 of corn is protein and 78.2 Ib. carbohydrates. Then 10 Ib. would con- 

 tain .1 of the protein and carbohydrates in 100 Ib. 



.1 of 7.81b.= .781b. protein. 

 .1 of 78.2 Ib. = 7.82 Ib. carbohydrates. 



From the table it is seen that 40 Ib. of every 100 Ib. of cottonseed 

 meal is protein and 40 Ib. carbohydrates. Then 3 Ib. would contain 

 .03 of the protein and carbohydrates in 100 Ib. 



.03 of 40 Ib. = 1.2 Ib. protein. 



.03 of 40 Ib. = 1.2 Ib. carbohydrates. 



From the table it is seen that 2.75 Ib. of every 100 Ib. of timothy 

 hay is protein and 46 Ib. carbohydrates. Then 15 Ib. would contain 

 .15 of the protein and carbohydrates in 100 Ib. 



.15 of 2.751b. = .4125 Ib. protein. 



.15 of 46 Ib. = 6.9 Ib. carbohydrates. 



.78 Ib. + 1.2 Ib. + .4125 Ib. = 2.3925 Ib. protein. 



7.82 Ib. + 1.2 Ib. + 6.9 Ib. = 15.92 Ib. carbohydrates. 



Making the protein the antecedent and the carbohydrates the 

 consequent of a ratio, we have 2.3925 : 15.92 = 6. The nutritive ratio 

 is 1 : 6. 



NOTE. A ratio may be reduced to its lowest terms by dividing each 

 term by the antecedent. 



