UNPUBLISHED FRAGMENTS. 433 



T i. T"> T 



I 4 t r^ 



Ijct i t > 



Let A = y // -y / , 



C/A P 



OV^O i 7 A 



OyO"' V "~ -^ (X^O L> D 1 * 

 ^1 JT 



The condition of no electrical current gives 



~x 



e T 



Apply to both ends and add, 



*" 



P+P' 1 



= o c oo^o p _ p-i ' 

 If we set, to abridge, 



When the summations are for cations or anions separately, the 

 last equation may be written 



which gives P 2 = 



Now 



^ is the part of the conductivity of the first electrolyte which is 

 due to the cations. 



If the first electrolyte contains only one cation Q and one anion ( 2 ), 

 and the second only one cation ( 3 ) and one anion ( 4 ), we have 



or, since Cl y/ = C 2 y 2 ' = C 8 y 8 " = C 4 y 4 ", 



r ,_ Fs=1 



v to k 



like the formula which you quote. 

 G.I. 2E 



