DAIRY HERD 



39 



Amt. in 



100 Ibs. 



Carbohydrates in 9 Ibs. bran = 39.2 x .09 = 3.528 Ibs. 



Carbohydrates in 1 Ib. c. s. meal = 16.9 x .01 = 0.169 Ibs. 



Carbohydrates in 4 Ibs. corn = 66.7 x .04 = 2.668 Ibs. 



Carbohydrates in 30 Ibs. corn silage = 11.3 x .30 = 3.390 Ibs. 



Carbohydrates in 5 Ibs. corn stover = 32.4 x .05 = 1,620 Ibs. 



Carbohydrates in 5 Ibs. clover hay = 35.8 x .05 = 1.790 Ibs. 



Total carbohydrates =13.165 Ibs. 



Standard =13.00 Ibs. 



Ether extract in 9 Ibs. bran 

 Ether extract in 1 Ib. c. s. meal 

 Ether extract in 4 Ibs. corn 

 Ether extract in 30 Ibs. corn silage 

 Ether extract in 5 Ibs. corn stover 

 Ether extract in 5 Ibs. clover hay 



To make the above calculation perfectly plain it should 

 be noted that the table on page 35 says that 100 Ibs. of 

 bran contain 12.2 Ibs. of protein. If 100 Ibs. contain 12.2 

 Ibs., 9 Ibs. of bran will contain nine hundredths of 12.2 

 Ibs. or .09 x 12.2, which equals 1.098 Ibs. of protein. The 

 method is the same in the remaining computations. 



Nutritive Ratio. In speaking of rations, the terms 

 "wide" ration and "narrow" ration are frequently used. 

 The terms refer to the proportion of nitrogenous to non- 

 nitrogenous matter in the ration. This proportion is 

 spoken of as the nutritive ratio, which is obtained by 

 dividing the digestible carbohydrates plus 2.25 (heat 

 equivalent of carbohydrates) times the digestible ether 



