MISCELLANEOUS WORK 199 



Triangle ABD = 506 X 2 = 50,000 square yards. 

 500x200 



3 



= 1,500 

 x 60 = 3,300 

 HGON = 6 --+l? x 60 = 3,900 



7A 4. fiO 



ou x 60 = 3,900 



+ 5 



x 60 = 3,300 



Triangle ELD = ^--L v = 1,750 



117,650 



117,650 square yards divided by 4,840, the number of 

 square yards in one acre, gives 24*398 acres as the area 

 of the ground. 



The area of the irregular figure containing the four 

 trapezoids may be found by taking the mean length of 

 the two extreme offsets PI and LE viz., 50. Add to 

 this the sum of the other offsets viz., 190 making 240; 

 multiply this figure by the extreme length of the figure 

 viz., 240 and divide by the number of spaces between 

 the offsets viz., 4=14,400. 



To measure the same ground from the outside, it is 

 necessary to erect a square or parallelogram of known 

 dimensions upon one of the sides. 



Taking the line BC as the base, it is measured and found 

 to be 445 yards. From B and C perpendiculars are set 



