SIR B. C. BEODIE ON THE CALCULUS OF CHEMICAL OPERATIONS. 821 



anil 



m=2, Wi=l, 



n=l, «i=2, 

 a minimum. 



Hence the symbol of nitrogen as determined from this equation is av^, and the symbol 



of ammonia is a^v. 



Since the density of ammonia is 8'5, 



2+w(v)=8-5, 

 and 



The general solutions of the above equations give 



m=2+t, ?Wi=l+^i, 



n=l+2t, ^1=2(1 +^i), 

 whence we have as the 



Symbol of ammonia . . . a^'^V'''*', 



Symbol of nitrogen . . . a>+V<'+''', 

 and 



6-5-/ 



where t is not > 6, and ^, not < 0. 



» 



M0CCCLXV1. 5 * 



a- 



