BOOK V. n. 6-8 



diameter (that is, the measurement across) is 70 

 feet. Multiply this number by itself: 70 times 70 

 makes 4900. Multiply this sum by 11 and the result 

 is 53,900 feet. I subtract a fourteenth part of this 



sum, namely 3850, and this I declare to be the 

 number of square feet in the circle, which sum 

 amounts to a sexcuncia of a iugerum and two scripula 

 (T44) ^i^d a \ia\i scripulum (5^).* 



If the piece of land is to be semi-circular and its 

 base measures 140 feet and the depth of the circular 

 portion is 70 feet, it will be necessary to multiply the 



140 feet 

 depth by the base. 70 times 140 makes 9800. This 

 sum multiplied by 11 makes 107,800, and a fourteenth 

 part of this is 7700. This we shall say is the number 

 of square feet in the semi-circle, which makes a 

 quadrans (^) of a iugerum and 5 scripula (288)-'' 



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