BOOK V. III. 3-7 



201 and 21. These sums you will multiply together, 

 21 times 201, and you will get 4221. This, you will 

 say, is the number of plants required. 



Similarly, if you wish to set them seven feet apart, 

 you will take a seventh of the length and of the 

 breadth and you will add the angular units, and by 

 the same method and the same arrangement you will 

 make up the number of the plants. In a word, how- 

 ever many feet you have decided for the distance 

 between the plants, you will take the total length 

 and the total breadth and add the units mentioned 

 above. This being so, it follows that the iugerum of 

 land, which is 240 feet long and 120 feet broad, if the 

 distance between the plants is three feet (and this 

 we consider to be the smallest distance which should 

 be left when planting vines), will accommodate 81 

 plants in its length, and in its breadth, with a dis- 

 tance of five feet between them, it will hold 25 plants. 

 These numbers when multiplied together make 

 2025. 



If the vineyard is arranged with intervals of four 

 feet each way, the row which runs lengthways will 

 contain 61 plants, and the row which runs breadth- 

 ways 31 plants ; this gives 1891 vines to a iugerum. 

 If the vineyard be laid out so that there are intervals 

 of four feet lengthways and five feet breadthways, 

 the row which runs lengthways will have 61 plants 

 and that which runs breadthways 25 plants. If the 

 planting is carried out with intervals of five feet, the 

 row will contain 49 plants lengthways and 25 breadth- 

 ways ; thetwonumbersmultipliedtogether make 1225. 

 If, however, you have decided to lay out the same area 



' si ac : om. SA. 



25 



