APPENDIX. 267 



In order to make the above formula more intelligible : 

 Let L = 80 rods or 1330 feet. 

 " H = 50 feet. 

 " D = 2 inches. 

 " Q =: gallons. 



Then Q=:0.608./(32X^) =0.67; or, the same may be thus 



expressed in words. 



Divide the height (50) by the length (1320); multiply the quotient 

 by the fifth power of the diameter (fifth power of 2 = 32) ; extract the 

 square root of the product, which, being multiplied by 0.608, will give 

 (0.67) the number of gallons the tube will discharge in one second ; 

 which in this case is 40 gallons in one minute. 



THE END. 



