36 



SMITHSONIAN MISCELLANEOUS COLLECTIONS 



VOL. sr 



Attributing to x different values we find the point of saturation by- 

 comparison with the following table, which contains the values of 

 t corresponding to the maximum tensions of aqueous vapor. 



1 



We can adopt — = 0.29 approximately and calculate a table of 



the quantity v determined by the formula 



273 +r 

 v = _i 



f m 



We shall find 



v - 133.6; / - 14.4 mm ; r = 17°; p = 733.4 ram ; h = 306 m 



(2) The air is saturated above o°. 



By substituting in equation (6) the value of x from equation (7) 

 and assuming 



$ = 0.0125 = * ; t - 17°; r = 0°; / 0= 14.4 mm , 

 p = 733.4 m and / = 4.60 mra 



we shall find 



40.05 

 log (p-f) - 2.6005 + ■— 



and 



p = 487. 2 mm ; x = 0.00594 



Formula (12) gives h = 3384 meters. 



If we had used formula (17) we should have given m the value 

 6.36. 



(3) Water freezing to ice at o°. 



By substituting in equation (9) the values 

 f - 0.0125, x = 0.00594, y = £ - x = 0.00656, f = f = 4-6 mm 

 we shall find 



* - 0.00607 kg. and from formula (7) p = 476. 5 m,n 



Formula (13) gives h = 178 meters. 



