MOVEMENTS OF ATMOSPHERE GULDBERG AND MOHN 



241 



Let us consider the special case in which M and N are independent 

 of the time and make 



r) = and £ ' = W 



Then by placirig N' = o and by comparing the formula for 

 tan /?' with the first formula for tangent a we have /?'=/? and by 

 eliminating 2(o sin 6 between the equations (18) and (19) we shall 

 find 



k U ( UV a 



S " "T^ .---)=-■ G x (27) 



cos p r \ r I p 



P = \ x 



U X W 

 S 



cos p 



+ [ y - v - 



u x w 



s 



sin t 3 J (28) 



and by introducing the barometric height b in place of the pressure 

 p, in equation (23) we have 



b - K 



h G x P. 



(29) 



We infer from these equations that the system of isobars belong- 

 ing to the stationary cyclone 

 has been transferred from the 

 ->. DC origin (see fig. 51) to the cen- 

 ter A, whose distance is 



P u 

 fi G 



and which falls on the right 

 line A making the angle /? 

 with the direction of propaga- 

 tion of the center of the cy- 

 clone. 



Example. Assume that the cyclone has a velocity of propagation 

 W = 15™ and that we have for its exterior portion, U r = 150 and 

 a = 48 and for its interior portion U x = 3 m ,G x = o.483 mm , /?= 57°.5 



we shall find 



A = 0°.85 



By constructing the isobars for the exterior part and for the 

 interior part we shall by interpolation find the isobars for the inter- 

 mediate region. 



