ON THE ENERGY OF STORMS MARGULES 559 



Initial stage 



mm 



Po - 76o* pi = 59i.69o mm p h = 450.222 



r 02 - 283* r i2 = 263.1315 7^=260.1315° 7^ = 240.2630° 



/?!* = 2000 meters h 2 * = 2000 meters 



Final stage 

 p Q = 7 6o mm />/ = 618.532™ p 4 =450-222' 



^'01 = 279.773° 7^ = 263.509° 

 /i' t = 1637.17 meters 



T' i2 = 266.548° 7', 2 = 243.o34 c 

 /V 2 = 2366.97 meters 



C p 1 



(P + I) = — . --—— . p h .233 . 5132 + Constant 



a g 1 + K 



- - C p ! 

 (P4-I) =-.- . p fc . 233 . 4140 + Constant 



g 1 + AC rh 



Ph 1 



J T 2 = ■- — . . C„ 0.0992° 



whence V = 14.85 meters per second. 



This computation is laborious because the conclusion depends on a 

 small difference between large quantities. We may find V by a 

 shorter method without previously computing a number of other 

 quantities as in the next following article. 



§(22) Approximate method of computing V. We first assume that 

 each of the masses 1 and 2 is initially in stable equilibrium but that 

 the greatest entropy in 1 is smaller than the least entropy in 2, so 

 that as before in the final stage the whole of i' comes to lie below 

 2' '; the serial order of the strata in each of the masses will be re- 

 tained provided the overturning proceeds isentropically. 



Let p l and p\ be the pressures for the same layer in 1 and i', 

 or in the initial and final stages of mass 1 respectively, and similarly 

 T t and T\ for the corresponding temperatures. Let p 2 ; p' 2 \ T 2 ; 



