ON THE ENERGY OF STORMS MARGULES 



589 



§(37) We now pass to the computation of the available kinetic 

 energy of an extended horizontal System (fig. 1). 



First analysis. Initial stage. Chamber 1 contains dry air, 

 chamber 2 the fictitious gas; both of these are in neutral equilibrium, 

 and both uader the same pressure p h at the altitude h. The tem- 

 peratures are to be so chosen that, after the overturn, in the final 

 stage, 2' lies wholly above 1' and p h remains unchanged. Therefore 

 if the serial sequence of the elementary layers be unchanged, every 

 layer of chamber 2 expands except the highest one which retains 

 its original pressure. The layers of i' and 2' are individually in 

 the condition of neutral equilibrium. As regards 2' this result 

 follows from the application of equation (ia), §36. 



Let (Q) be the quantity of heat added to the mass 2 by its expan- 

 sion, then for the available kinetic energy of the whole system we 



have K + R = (Q) - d (P + I) 



/;/ 



(vy 



C p { j(T t - r)d» h +j(T 2 - T')dm 2 } 



The given data are h, p h , T hv T h2 , X, and /?; whence for the initial 

 stage we find 



T M = T h . 1 + k 



T m - r M 1 + ; 



RT 



Pol = Ph[ l + * 



gh \k 



Po2 = Ph 1 +^ 



h \ a 



RT t 



For the final stage wc have 



At the base 



P = h {Pox + P02) 



Temperature 

 T h 



Hz 



TL = 7\, 



T' = T 



hi 



Ph 



T h . = T i»\j h 



Ky 

 ph' 



