Untformly Valtd Soluttons of Laplace Equatton 
Te 2 ae a 
2a 7a 
is a stream line 
Figure 1] The local problem for a symmetric 
leading edge 
2 
Using the conformal mapping z= $ , the given parabola is transfor- 
med into the straight line § = 1/ V2\|a2l and the corresponding 
complex potentialis f£(')=e (5) +iw(e) 
£ (5 )\y= = siaee(. <2 cy + Cste 
with 
bo = = ti 
0s fal abies v0 
So, the solution we are looking for is: 
- = = fl y 8. 8 
= - gi -2P (| —— —+ 2p in— 
®, sin X k Z ci =i coss Bos + K «| 
and rewritting it, with the coordinates Nej0Z03 
4 
® = R{-sindz + 2¢ er ie) (40) 
1 0 z lal 
The identification with the asymptotic behaviour (39) at infinity gives : 
6 - hi . id : 2fg 
) 2 Tani which is identically satisfie 
Bo = d,(s) if. which gives the position of the stagnation 
point P. 
In the physical plane Y , Z, P is located at the point 
(eds 4d, / W/ 2g!) 
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