Falttnsen 
We see that (89) matches with (83) if we set: 
7 (x) 
and 
Se ie. Tae ae ae 
a fiat = 3 ea Neae (x) 
Sy 
2w wee lx -€| (91) 
Equation (91) gives us Abel's integral equation to solve. 
B, (x) on the right-hand side of (91) has to be numerically deter- 
mined (see (90) ). We are only interested in the fact that the near- 
field and far-field solutions match, and we are not going to find o, 
It is the near-field solution that has the primary interest and 
we have found that a two-term near-field solution of the diffraction 
potential is 
1798 
