Falttnsen 
in the fluid domain, and the boundary conditions 
Op | " 
vg t ay a when y = 0, |x|> a (94) 
and 
d¢ é. 
Erp, es when r=a, - w/2 < 6 <x/Z (95) 
He shows that a solution of (93), (94) and (95) can be written in 
the form 
sco 
d= B, \A S_(x, y) + exp (- vy) +> A On y)} (96) 
19 0 
The functions S(x,y) and O,,(x, y) will be discussed presently. 
Ursell considered an infinitely long cylinder and there were 
no appropriate conditions for x—»> oo that could determine the ar- 
bitrary constant B, in (96). But we consider a ship, and we have 
found a condition non x—>+toothat will determine B, . This is si- 
milar to what we did in finding the solutions (48) and (92). Then we 
used an integral equation approach to solve (93), (94) and (95). 
But for this special case with a circular cross-section it is more 
convenient to write the solution as (96). We will later come back to 
the determination of B after we have discussed the terms in (96) 
some more. 
The source term Se can be written as 
cos (Coan. L 1 
S, (ro (lee ve f f] core in S exp(-vy cos hu + ivx sin hy) dv 
=c0) = 60 (97) 
1800 
