Distribution of Hydrodynamic Forces on a Shipmodel 



Fn - .15 



S 



2 3 t I 5 



Fn = .20 



^ 1 1 n 3 -^- rrTTT77 



5 







-5 



-10 



t = 





 -5 



6-'° 



OT 



-10 



"q) 5 





 -5 

 -10 



f 5 







-5 



-10 



s: 



^ 



LO- 4 r ad/sec 



UJ: 6 rod /sec 



OJ = 8 rod/sec 



■ O) = lOrad/sec 



<^ = l2rad/sec 



z: 



;2' 



Z^^ 



zs. 



Fn = .25 



Fn = .30 



h . I . I 3 I . I sTT I . I > > 1 I a I 3 I . I i =F 



Fig, 10 - Distribution of e over 

 the length of the shipmodel 



235 



