HARMONIC ANALYSIS AND PREDICTION OF TIDES 111 
312. In finding the difference between the longitude of the time 
meridian (S) and the longitude of the place (Z) consider west longitude 
as positive and east longitude as negative. In the ordinary use of 
form 244 it is assumed that civil time has been used in the tabulations 
of the observations. If, however, the original hourly heights as 
tabulated in form 362 are in accordance with astronomical time in 
which the 0 hour represents the noon of the corresponding civil day 
and the 12th hour the following midnight, form 244 will still be 
applicable if the longitude of the time meridian (S) is taken equal to 
the civil time meridian plus 180°. For example, if tabulations have 
been made in astronomical time for a locality where the civil time is 
based upon the meridian 15° E., the value for S should be taken 
as — 15+ 180, or 165°. If tabulations have been in Greenwich 
astronomical time, S should be taken as 180°. 
313. Form 244a, Log F and arguments for elimination (fig. 15).— 
Items (1) to (11) are compiled here for convenience of reference for 
Form 244a 
DEPARTMENT OF COMMERCE 
U. S. COAST AND GEODETIC SURVEY 
TIDES: Log F and Arguments for Elimination 
Station -....... Morras iC at fo rrid a: at SNe oe a Sie SIRT ie oS Ne ae ad RR Ey apo as 
yr. nm. d. b. 
Length of series __._.... 163. days. Series begins ................-.----------0--. 1919... Feb. 13. O. 
Component Log F Component Log F Component Log F 
(4 dec ) (4 dec.) (4 dec.) 
TA gieee er erae dee ek 0.0201 Whe 6 6 eo otal chore MKic. nvssvceesers 0.0092... 
Go ono oee lo dled 0-0160 Nz, 2N _...9° 9952 2M Kerem “cnreuns 0.0023... 
Ks 0:0472 Oh oo o foo soles QO. 0264 INOS) g) Gila §5 ad 9 9863... 
L,=Log F(M:)+(7) |...9:9589 OO i aise tess oa 30-0929... MS,2SM . . .« |_.9.:9932___._.... 
M,=Log F(0,)+(8) |..9:8856 | Phusiinaybaueenestes 0.0000 NE 65 6 6 o LO EES 
i] 
Maj se 9 9952 eel Qi2q) ys ey mONOR6d ES mst... . «(99982 
Mine fre ner tan [OS 9.9897 | R:, 8), 82, S4, Se,T: | 0.0000 Mine xsresnusuee er | = 9.9772... 
M..... .4|..9:9863_ Move sw se | 9 99S2 Sa,Ssa . . « -| 0.0000 
SY ge SE Sok eal Hie 9-9794 pL 0- 0264 
(1) = N=item (6) from Form 244=...245° 011. (2 dec.) 
(2) = 7=item (7) from Form 244 =......21.:.76_........ (2 dec.) 
(3) =P=item (12) from Form 244= ...55..903 (2 dec.) 
(4) =(h—4p’) =item (3) —} item (10), from Form 244=..........327° . (0 dec.) 
(5) =(h—r’’) =item (3) —} item (11), from Form 244 =..........331 (0 dec.) 
(6) = (h—p,) =item (3) —item (4), from Form 244= _......... Gal (0 dec.) 
(7) =Log R, from Table 7 =......9e9657..... (4 dec.) 
(8) =Log Q, from Table 9=_.....9e8592....._ (4 dec.) 
{9) = Natural number from Log F(K,) =...16038.....__.. (3 dec.) 
(10) =Log f(K,) =10—Log F(K,) = 9¢9528......... (4 dec.) 
(11) = Natural number f(K,) from (10) =..0.897......... (3 dec.) 
ExpLanaTIon.—For all tables sco Special Publication No. 98. First fill in items (1) to (8). Then 
obtain values of log F for all components excepting L, and M, from Table 12. Log F(L,)=log F(M,)+ 
log R,, and log F(M,) =log F(O,)+log Q,. Items (9) to (11) are obtained after the rest of the form 
has been filled out. 
FIGURE 15. 
