HARMONIC ANALYSIS AND PREDICTION OF TIDES ial 
constituents. The symbol A represents the constituent to be cleared, 
and the symbol B is the general designation for the disturbing con- 
stituents. The symbol applying to constituent A is to be crossed out 
in column (1) and entered in column (8). The values for items (9) 
and (19) are to be taken from columns (1) and (2) of form 452. 
327. For obtaining column (2) it will be found convenient to copy 
the logarithms of the R’s of B from column (8) of form 452 on a hori- 
zontal strip of paper spaced the same as table 29. Applying this 
strip successively to the upper line of the tabular values for each con- 
Form 246 
DEPARTMENT OF COMMERCE 
‘COAST AND GEODETIC SURVEY 
TIDES: ELIMINATION OF COMPONENT EFFECTS 
m d. h 
Peper LOR ebm NO ease ne Ole 
zat 
RB)x | Nat. No. 2)| Table 29 (5) (arxcn.(sy | @yxees (5) (8) 
Table29 | Table2? | —3(B:) | “+09 | “Tableso | ‘Table 30 RESULTS 
Tog (dec) | ft. dec) | nodec) | (modec.) | (dec) | (dec) | Use 4dec. for logarithms, 3 dec. for amplitudes, 1 dec. for angles 
Component A,;=.-Kee. 
(9) =R'(A;) from analysis 
(19) =(9) — (7) 
(11) =log (6) 
(12) =log (10) 
(13) = (11) — (12) =log tan 6 ¢ 
*(14)=6 
(15) =log cos 6 ¢ 
(16) = (12) — (15) =log R(A:) 
(16a) =log F(A2) 
(17) = (16) +log F(A2) =log H(A?) 
(18) = H(A:) 
(19) =¢'(A2) from analysis 
(20) = (14) + (19) =¢ (A2) 
(20a) =(V.+u) 
(21) = (20) + (Vo+u) =x(A2) 
ribbon 
Component A,=..12... 
(9) = R’(A;) from analysis 
(10) = (9) — (7) 
(11) =log (6) 
(12) =log (10) 
_{| (13) =(11) — (12) =log tan 6 ¢ 
| *(14)=6 ¢ 
(15) =log cos 6 
(16) = (12) — (15) = log R(A2) 
(16a) =log F(A2) 
(17) = (16) +log F(A2) =log H(A?) 
(18) = H(A2) 
(19) =¢'(A)) from analysis 
(20) = (14) + (19) =¢ (A2) 
(20a) =(V.+u) 
(21) = (20) + (Vo+u) =«(A,) 
Vit tnd ee pon ot 
in 
Component A,;= 
(9) = R'(A,) from analysis 
(10) =(9) —(7) 
(11) =log (6) 
(12) =log (10) 
(13) = (11) — (12) =log tan 6 ¢ 
*(14) =6 £ 
(15) =log cos 6 
(16) = (12) — (15) =log R(A2) 
(16a) =log F(A2) a 
(17) = (16) +log F(A2) =log H(A.) 
(18) = H(A2) 
(19) =¢'(.42) from analysis 
(20) = (14) + (19) =¢ (42) 
(20a) =(V.+u) 
(21) = (20) + (Vo+u) =x(A2) 
* 8¢ or (14) is in the Ist quadrant when (6) is + and (10) is +. Takako Feb. 28, 1921 
$f or (14) is in the 2d quadrant when (6) is + and (10) is —. Computed by 
8 or (14) is in the 3d quadrant when (6) is — and (10) is —. 
$f or (14) is in the 4th quadrant when (6) is — and (10) is +. 
When (6) is 0 and (10) is positive, (11) & (13) = — oo, and (14) & (15) = 0. BV Tne clio ase eee een ee 
FIGURE 19. 
