PROBLEMS m9 
4=91°; since this value is greater than 90° use the supplement as Z. Therefore, 
with Z=89° (as t) and L=28° enter Table I. 
eee 22° 48.4’(+) 
L..28°fb 1 528(—) A32815 C 5A #? (—) 221 
pep eon a5 GE) nB4tm2i|  D4i7 
(-4) dee. 9°39’ A+B 77527| C+D 471 71.8 
t = 69,2=4)37™ B, 
Oe 7 16 94 
Gaye ee 11 52 20 ° 
19 08 44 r 
Ct es (+) TOs 
ONE Ol ulyosee es oH YY 
C 
G. C. T 
ee Vi @lao Jee 19 54 02.5 
LNA I) sO a 1 LENG =e | 
G 
y/ 
* 
LS el CSE ae oe a Ziel 26501 
ome se Se oe (—) 11 59 08 
1 Dy tS yal eal a Tay iP 9 alsa M 
(Approx) ts 222552055 4 37H. 
(Approx.) BR. Al? oo - 19 49)\From Nautical Almanac star is identified as 
(Approx.) dec. ---.(+) 9°39’J Altair. 
Problem 15 (here Z is over 90°, hence 6 and ?#’ are negative).—A seaplane is 
making passage from San Juan to Hampton Roads. No sights were available 
until the morning after departure (November 20, 1928), when, through a break 
in the clouds ‘‘Procyon”’ and an unknown star were observed. The pilot esti- 
mated his D. R. position at the time of sight to be latitude 27° 35’ N., longitude 70° 
26’ W. Other data as follows: G. S. T. at time of sight (by G. S. T. watch) 
25 46™ 34s; corrected altitude 28° 52'5; bearing of star 120° (south and east). 
Required to identify the unknown star. 
Z 120° 
Z 60 h 28° 52°5(+) 
L 28 b 48° 1444(—) <A 19082 (Galil (—) 50°9 
h+b 14° 21'9(—) = B 60533 D 592 
d (—) 9° 12’ al — (—) 7829 
A+B 79615 C+D 709 
t= (—) 129°8 (Subtract 
from 180°) 
i= 50. 2=3520™ 48H. 
h m 5 
Gao eb c eee eee 14 46 34 
WOME ees ee eee (—) 4 41 45 
Ty FSV ese eee eee cd ee 10 04 49 
PANO RO Rene erie = fe ie OU eS 3 20 48 E. 
ADO pk TALE So Jes oe 13 25 37 
IADprOxcGce= = Sse ss G) 9° 12’ 
(Star is identified as Spica.) 
