Murthy 



We have taken the mass of the ACV to be m which may be split up 

 into 



m = m + m 



where m g is that part of the weight of the ACV which is supported 

 by the air cushion and m g the other part supported by the buoyancy 

 of the side hulls. As the cushion pressure is taken to be of 0( j8 ) 

 and the cushion area may be considered to be of order zero it is clear 

 that m, is of 0(0) 



1. e. m 



& 



1 

 where — a — is now of order zero. In a similar manner, the width 



of the side hulls is taken to be of small order 8 and the length and 



draught being of order zero, m is of 0( 8 ) 



m 2 

 i.e. m 2 = 8 (_) 



m 

 where again ^- is of order zero. 



8 



Also, 



I = m k 2 



where k is the radius of gyration in pitch (of order zero), so that 



m i 2 m 2 2 



I = 0(-J- k^ ) + 8(— ±- k Z ) 





wh 



ere L and I are the moments of inertia of the partial masses 

 1 2 



supported by the cushion and the side hulls respectively. 



Assigning the correct orders of magnitude to m and I in (IV. l) 

 and (IV. 2) we derive the following results : 



210 



