Propulsive Effects of a Rotating Mass 



Fig. 11 - Results of tests on the 

 same type of device as in Fig. 9, 

 but with a total weight of 450 

 grams and having two pieces of 

 lead weighing 20 grams each 



The phenomenon shown in the 

 preceding case is repeated here; i.e., 

 the back part of the car moves side- 

 ways toward the right or toward the 

 left, according to the direction of ro- 

 tation of the masses. In about 40 

 seconds, the back part of the car 

 moves sideways about 2 meters. This 

 means that if the car is approaching 

 to park at a pavement and its longi- 

 tudinal plane forms an angle of 30° 

 with the pavement itself, a device with 

 two masses is able to bring all of the 

 car to the pavement in a short time. 

 By changing the direction of rotation 

 of the two masses, the car is brought 

 back to the position of arrival. 



An indication of the efficiency of the device can be obtained in the following 

 way. Let us assume an automobile weight of 800 kg, and let us distribute 500 

 kg on the front wheels and 300 kg on the back wheels. K we assume a friction 

 coefficient between wheels and pavement equal to 0.60, the force necessary to 

 move the back part of the car sideways is equal to 300 x 0.6 = 180 kg. Since the 

 lateral displacement of 2 meters happens in about 40 seconds, the useful power 

 is 180 X 2/40 X 75 = 0.12 hp. The ratio of the powers is 0.80. 



Fig. 12 - Device having four 

 rubber-covered heels and 

 weighing 1275 grams, climb- 

 ing a sheet of glass inclined 

 at 59° 



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