H(0) 



-r, 



dx 



Joosen 



a Gj(x, z, y) e dz 



C(x) 



-k f dx r G2(x,z,0)e^'^(''/')(^°^^"^°^^>dz , 



~'- 1 Jc ( X ) 



where 



if^ + (i sin ^ - f J 



]k(z+iy sin 



and 



(i sin/3-fJe'^(^'^y^^"^> + (i sin0-f,)0,e-^'^('''^)" 



s/3 



^k(z +iy sin (9) 



The expressions for the force components become 



1677^6" 



[ dx dz r d^ dC f g(5)d£? Ja, e^"^'^)^"-^)"' 



J- 1 C ( X ) J- 1 C ( f ) ''0 t 



+ A 6^^'''^^^^''"^^^''°^^**'°^'^^ + A 3*^^''^*^'^^''"^^''°^^'^''°^'^^ 



+ A e^^'''^^^'-^''"^) '^"^ ^ "^^ '^"^ '^-' 



where 



g(9) = cos + cos /? 

 for the X component; 



g(^) = sin 6 + sin /3 



for the y component, and further 



Ai(^,5) = GiGi , A2(^,5) = G2G2, A3(^,0) = G3G3, A^C^,^) = G4G4. 



The bar means that the complex conjugate has to be taken. 



Applying the method of stationary phase on the inner integrals of F (5,6) we 

 obtain the result 



k^ 

 F^ = -i^ cos /? 



J" '" 1 ' 



•'-1 -^c ( X ) L 



Ai x.^U Ai X 



dz , 



and 



640 



