MATHEMATICAL PAPERS. I". 
the apparent given time and noon’; andif it is the forenoon, 
this difference muft be fubftracted from the fun’s right afcen- 
fion ; but if it is the afternoon, it muft beadded. If the mean 
longitude is taken, the mean time muft be ufed. 
-. 2x he nonagefimal degree of the -ecliptic (s its higheft 
point above the horizon, and is 9o* diftant from each point cf 
the ecliptic, where interfected by the horizon. This nonagifi- 
mal point is determined by a perpendicular to the ecliptic, 
which paffes through its poles and the poles of the horizon, 
the altitude of which point is meafured from the horizon, 
upon this perpendicular, = 
“PROBLEM. — 
3 —SÜ confequently the right afcenfion of the mid-heaven, d Rind 
the longitude and altitude of the D ew id degree of the ec- 
liptic. 
A GENERAL SOLUTION OF E FOREGOING a PaosLEM. 
tial colutel ien) ie ys of de cquitof "and. of. the ecliptic 
will be in the plane of this circle. Let the diameter E2Q_ 
reprefent a portion of the ‘equator ; sav a portion of the ec- 
liptic ; P, thenorth pole of the equator 5 Pe the north pole of 
the ecliptic ; S and L their fouth poles. Let the are Pc S 
mark the right afcenfion of the mid-heaven, from the neareft 
 equino&ial point ; then this arc will reprefent the aee of 
fome place, at a given time, and c and w will be the culmina 
hs edet. uie ex E ME Lig usd M. Ne du 
