22 HANDBOOK OF MECHANICAL DESIGN 



13. Inside Part of a Torus. 



T Volume = 2irr 



-g D 



i 



WR\^, = TTpr^ 





4 \2 



D 



-A'): 



14. Circular Segment about an Axis through Center of Circle. 



'^ 12 X area -^ 4r"" 



Gravity 

 axis 



-■i! 



c 



a = 2 sin ^ ;^^ deg. 

 ZK 



Area = 



i2= 



a 



c 



114.59 2 



i^- 



4 



(a) Any material : 



FE^_. = pT 

 (5) For steel: 



229:2 " 6 r^"^ ~ 2 / 2 V^ 4 _ 



WP2 = i 



229:2 ~ 6 V^' ~ Y; 2 V^ 4 



15. Circular Segment about Any Axis Parallel to an Axis through the Center of 

 the Circles. (Refer to 14 for Figure.) 



WR%.-.' = WR\_. + weight {r' - r^) 



16, Rectangular Prism about an Axis Parallel to the Axis through the Center of 

 Gravity. 



Volume = WLT 



-W 



AT 



(a) For any material: 



L 



y 



-j-x 



WR\_. = pWLT [ ^' ^"^ + if) 



(h) For steel: 



^^^-- = 3:534 1-^2— + n 



