402 
PROPAGATION THROUGH THE STANDARD ATMOSPHERE 
Sega gee esate See 
| HH at 
ch VV 
Lt /\/| AM 
HM 
a SSS ces Sea 
ho IN METERS—————_> 
a 
fo} 
a 
° 
fo) 
lB AH bie Gras Ee Ba 
nN 
fo) 
nial ny. [| S 
=a au aise : 
il) (FATA FOR 20 log A=-I30 
pean] LTA ia aaa X=! meter 
|_| HORIZONTAL POLARIZATION 
n n i | li 
i 100 200 400 600 1000 
d IN KILOMETERS—> 
Fieure 27. Maximum range versus receiver height hz for given values of transmitter height hy. 
equation (136) is found to be 
p = 0.08127 
» = 47.35, d = 1,065 km 
D = 0.9851 
s = 0.00184 
ips 2,772 
hy 
he = 83,160 meters 
3. Vertical polarization, p # 1, @ # 180° (sea 
water). The procedure given here is first to find 
the position of the point for a given n assuming the 
reflection coefficient to equal —1 and then find the 
shift caused by the change in the reflection coeffi- 
cient. For the most important case, n = 1, the new 
maximum distance is given by 
d = dy(1 + pD), (188) 
