Zllustrative Example 
To illustrate the use of these results in selecting a 
cable configuration to meet given requirements,consider the 
case where it is desired to attain a depth of 5,000 feet at 
a towing speed of 10 ft/sec. 
Unfaired Cable 
From the curves in Appendix II we can determine the 
£ 
values of qe and S, corresponding to a value of y, = 5000 ft 
for each value of Ty These values are given in Table IV. 
T Iv 
gd x 105 d a 8 To Om 1 
ve a= 2 
sec* /it £t in. ft lbs/£t? lbs 
225 .0225 .270 22,500 (8) 9) 
40.0 .0400 . 480 13,900 2.06 3,300 
Ale 5 .0715 .857 9,300 2.54 13,000 
114 sigs 137 7,000 2.64 34,300 
166 . 166 1.99 6,000 2.70 74,500 
These results may be cross plotted and a particular 
configuration selected on the basis of a compromise between 
the length of cable required, the down force required, and 
the size of electrical core desired. 
29 
