THOMAS] PLATE 24, DRESDEN CODEX (om 
The remainder, 8 ahaus and 2 chuens, equals 2,920 days, and is pre- 
cisely the same as the difference between the preceding columns. As 
the date reached by column C2 was 3 Ahau, the 3d day of Pop, the first 
month in the year 1 Ezanab, we subtract as before 362, the remaining 
days of the year 1 Ezanab, from 2,920. This leaves 2,558 days, or 7 
years and 3 days. Counting from the year 1 Ezanab (table 3), 7 
years, we reach 8 Ben, the next year being 9 Ezanab. Counting down 
the figure column headed 9 (table 1), 3 days, we reach the numeral 
11 and find Ahau opposite in the Ezanab column. ‘The day reached is 
therefore 11 Ahau, 3 Pop, the first month of the year 9 Ezanab, and 
corresponds with the day at the foot of column B2 in the plate. 
As the difference between column A2 and Bz2 is precisely the same 
as that between the other columns (8 ahaus 2 chuens), we have only 
to count 7 years and 3 days from the close of the year 9 Ezanab. This 
brings us to the 3d day of the month Pop in the year 4 Ezanab, which 
we find, by referring to Table I, to be 6 Ahau, corresponding with the 
day at the bottom of column AY. It must be remembered, however, 
that the years mentioned have been those following the arbitrary 
selection for convenience in calculating, as nothing has been discoy- 
ered in the series to determine these. This could be ascertained if 
the top series were uninjured, so as to carry on the count to the 
lower left-hand series, which have definite dates. 
Passing now to the upper division of our figure, we notice that the 
day at the bottom of each column is 1 Ahau and that the day place in 
each is filled by the oval symbol, denoting, according to our interpre- 
tation, naught. As the series ascends toward the left, the columns 
will be taken in the same order as those of the lower division. We 
therefore subtract D1 from C1: 
Cl D1 Diff. 
Katunsteesse 4 1 3 
AUS See ee 12 5 7 
Chuens22-25 = 8 5 3 
Dayeaaeeeae 0 0 0 
The difference is 3 katuns (=21,600 days), 7 ahaus (=2,520 days), 3 
chuens (=60 days), and no odd days. The total is 24,180 days. As 
the number is large, exceeding a 52-year period or calendar round, we 
can subtract the greatest possible number of these periods (in this 
case only one) without in any way affecting the result so far as reach- 
ing the proper date is concerned, but the number of years thus 
embraced are to be counted in making up the true interval between 
the dates. 
As 1 Ahau may be the 3d day of the first month (Pop) of the year 
12 Ezanab, we select this as our starting point. 
One calendar round equals 18,980 days, which subtracted from 
24,180 leave 5,200 days. Taking from this number 362—the remaining 
