THOMAS] PLATE 62, DRESDEN CODEX 25 
folds of a serpent (the one to the right), and consists of two series, 
one black, the other red. These have also been calculated by Dr For- 
stemann and arranged according to the order of units as given here. 
Mr Goodman’s names are given opposite and differences to the right. 









Black Red | Difference 
Days 
| Great cycles .__..- | 4 4 0 equals ---- 0 
Oy clesa. sme. 1525 6 6 0 equals _--. 0 
| Sains eee eee 9 1 8 equal.-_--- 57, 600 
Wee ausseeee kee ce 15 9 5 equal-_-_--- 1, 800 
@huensses. -sa5=5: 12 15 15 equal .=-- 300 
DaySeaeienee ae a5 19 0 | .19 equal ---- 19 
= =) & 
Days below-..---- 3 Kan | 13 Akbal | Dotaleee==- 59, 719 
NOMI easssésccs 16 Uo 1 Kankin 
Dr Foérstemann’s totals are as follows: 
SILVA (se oe ee an Soe eMeciasE GE aa Sate 12, 454, 459 
TREC ee te area rh eee te A= eee che eel ne eee ee 12, 394, 740 
MUiienence yee anes see ee eee eee 59, 719 
showing his result to be precisely the same as that obtained by using 
the Goodman periods, or rather showing the Goodman periods to be 
precisely the same as those used by Dr Férstemann with one excep- 
tion. Before proceeding, it is necessary to notice that the day Kan is 
never the 16th day of the month, but may be the 17th, therefore the 
date 3 Kan 16 Uo, under the black column, must be changed to 3 Kan 
17 Uo. In this example the counting must be backward in the order 
of time if we proceed from the lower to the higher series. 
Subtracting 3 calendar rounds (56,940 days) from 59,719, the differ- 
ence given above, the remainder is 2,779 days. 
As 13 Akbal 1 Kankin, is the first day of the fourteenth month of 
the year 13 Akbal, we count backward from this date. In counting 
backward, if we start with—that is, include—the day named, the day 
sought will be the next beyond the last day counted. As 1 Kankin is 
the two hundred and sixty-first day of the year 13 Akbal, we subtract 
this number from 2,779, and, dividing the remainder by 365, obtain 6 
years and a surplus of 328 days, taking from this the 5 added or inter- 
calary days there remain 323, or 16 months and 3 days to be counted 
back on the year reached. Counting back on our table 3 6 years from 
the year 13 Akbal, we reach 7 Ben, the next year being 6 Lamat. 
Subtracting 16 months and 3 days from 18 months, the remainder is 1 
month and 17 days; hence the day reached will be the seventeenth day 
of the month Uo in the year 6 Lamat. This, by reference to table 1, 
19 ETH, PT 2 11 

