All-101 60 



Differentiating (0) with respect to x, (9) with respect 

 to y, and substracting , v;e have 



e[V, + V, - U^ - U. ^^^, J - V. = sin nsy (11) 

 Ixxx Ixyy Ixxy lyyy -• l 



which is equation ('+,16) with a = 0» 



Thus the transport distribution for the steady case is 

 precisely the same as it is in Problem 1. The difference in 

 behavior enters into the non-steady case when the motion of the 

 interface affects the motion of the water in the top layer. 



If we set 0=0, then equations (^,22) and (^.23) are 

 the solutions for the present U^ V-|^, Similarly with a = 0, 

 from equations (8) and (9) above 



nsX ._2 



where H^ is given by (^.26). Then H-]_ may be written 



2ns\ 





However, if 2n^/eb Hq < 1, then H]_ may be written 



approximately 



Q + [© + i^ H ] 

 H^ =; - . = H„ . (12. a) 



b 

 Hp can then be evaluated by 



H^ = - I H, . (7) 



2 b 1 



If the dimensional constants* which were used in Problem 



* The depth {Viy-^z^ ^^ given the same value as D in Problem 1, 



