All-101 72 



They are ] 



- (^ 6 +2A+2B) +\ {h 6.+2A+2B)^ - 2(A+B - - +2) 

 D ^ = -' V 3 -^ 3 



^ 6.4-2A+2B + \/(^ 6t+2A+2B)^ - 2(A+B- 4-2) 



D^ K = -J = i— 3 i ^ 3 



3?^ 2 



where 



'.2 "" 3 27 



> 2 "^ 3 27 V 4 3 ^^ ^2 + 3 27^ 



The above solution for hp must now be substituted into 



the previous six equations and the boundary layer contributions 



for u , V , h ^ can be derived by keeping the parts which ■ 

 1)2 1,2 1,^ 



— ^ as C — >co . If the interior and boundary layer solutions 

 are added, the C. can be evaluated by means of the boundary 

 conditions U-j^ = V-j_ = U2 = V2 = on x = 0,r, 



Practically, this is an almost impossible task, and 

 numerical methods must be employed for the whole procedure. 

 In viev; of this fact, nothing is gained by the analysis and the 

 entire solution might as well be carried out numerically from 

 the very beginning. 



