1. Select the salinity interval of 30.00 to 39.99%o, page 24. 



2. In colunnn one find the temperature interval in which 19.90'*C 

 falls and round to the nearest (upper in this example) limit of the 

 interval or 20.00''C. 



3. Entering colunin one at 20.00'C read the corresponding L- value 

 of .0417 in column two. This is the correct L- value for the base of 

 the salinity interval, that is, for a salinity of 30.00%o and temperature 

 of I9.90"C. 



4. To find the correct L- value for the given salinity of 34.26%o, 

 multiply the designated f-factor (.001216) in column three by the last 

 three digits of the given salinity (4.26), observing decimal places, 

 and add the value obtained to the base value .0417. 



5. Round the value obtained (.04688016) to four decimal places. 

 ANSWER .0469 . 



Thus: Given 19.90-0 and 34. 26%o S. 



From table for Salinity 30.00%o to 39.99%o, enter column one 

 at nearest limit of temperature interval (20.00). 



obtain base / f-factor last three 



L- value in / of column digits of 



column two + I three x given S. 



.0417 \ .001216 4.26 



.04688016 (round to four decimal places) ANSWER .0469 



20 



