36 
where: 
an Sy lay Pia = va Cla). 1° = eh) and roc, Me) 
ni 
These can be solved simultaneously to give: 
Rie (As aia) 
1 2 n1 n2 12 11 
Dia (Poe FP) a [iran eae Meas WS = 
-7 
n2 ni 
(A6) 
1 
2 
trae 
og (Oy aniie) 
——— (A7) 
n = 95 Sis 
For the remaining beads, formulae (A2) and (A3) may be used pro- 
vided that one takes: 
R=, +b,, and =m, +b, (A8) 
Note that it may be possible to get a negative value for ) in equation 
(A2). This would happen if the 7 (7) curve lies quite close to the 
one farthest to the right, and is appreciably less steep. It must 
be rotated less to get it parallel to curve 1. As pointed out before, 
the rotation is accompanied by a translation to the left. If the ro- 
tated curve falls to the right of the rotated curve 7 (or what is 
equivalent to curve 1, translated b, to the right) it cannot be trans- 
lated to the left except by a negative series resistor. In sucha 
case, this curve must be used in place of the one farthest to the 
right in computing b, and ay. 
Note that the only rotation of a curve possible is clockwise. 
This reduces sensitivity. The curve chosen for zero rotation is the 
steepest curve; the other curves can be rotated into parallelism 
with it, but it cannot be rotated into parallelism with any of the 
‘others. The value of b, obtained here is minimum. Values larger 
than this would give equally well compensated curves. The proper 
