NOTES ON CHAIN CABLES. 



159 



force Q. There will also be at this section a bending moment M, which can be de- 

 termined from the ecjuation : 



M=Qd 



l(l-cos.)+lcos.c-.^^(l+l)-(l + J-)(i-.) 



Now, consider any other normal section, as C, and consider the part of the 

 link between sections A and C a free body. At C, let two forces, each equal to Q, but 

 opposite in sense, be added to the system. One of these forces with the force Q at 

 section A forms a couple whose moment is Qh; the other force is resolved into 

 components, one Q cos <^ along the section ; the other Q sin <i> normal to the sec- 

 tion. The component Q cos </> produces shearing stress and is neglected. At the 

 section C we have, therefore: 



A normal force P = Q sin <^. 



A bending moment Mb = Qh + M. 



With P and Mb known, the intensity of stress at any fiber is determined from 

 the equation: 



Mb _^Mb ^ 



fr zfr r-^y 



or less exactly but more sifnply from : 



-7- 



My 

 I 



Table of Distribution of Stress in Open Link. 



