MORLEV] INTRODUCTION TO STUDY OF MAYA HIEROGLYPHS 145 



Let US count forward the number 5,799 from the starting point 

 2 Kan 7 Tzec. It is apparent at the outset that, since this number 

 is less than 18,980, or 1 Cakndar Round, the prehminary ruk^ given 

 on page 143 does not apply in this case. Therefore we may proceed 

 with the first rule given on page 139, by means of which the new day 

 coefficient may be determined. Dividing the given number by 13 

 we have: 5,799 -^ 13 =446tV- Countmg forward the numerator of the 

 fractional part of the resulting quotient (1) from the day coefficient 

 of the starting point (2), we reach 3 as the day coefficient of the 

 terminal date. 



The second rule given on page 140 tells how to find the day sign of 

 the terminal date. Dividing the given number by 20, we have: 

 5,799^20 = 289^. Counting forward the numerator of the frac- 

 tional part of the resulting quotient (19) from the day sign of the 

 starting point, Kan, in the sequence of the twenty-day signs given 

 in Table I, the day sign Akbal will be reached, which will be the 

 day sign of the terminal date. Therefore the day of the terminal 

 date will be 3 Akbal. 



The third rule, given on page 141, tells how to find the position 

 which the day of the terminal date occupied in the 365-day year. 

 Dividing the given number by 365, we have: 5,799 -^ 365 = 15|-||. 

 Counting forward the numerator of the fractional part of the resulting 

 quotient, 324, from the year position of the starting date, 7 Tzec, in 

 the sequence of the 365 year positions given in Table XV, the position 

 6 Zip will be reached as the position in the year of the day of the 

 terminal date. The count by means of which the position 6 Zip is 

 determined is given in detail. After the year position of the starting 

 point, 7 Tzec, it requires 12 more positions (Nos. 8-19, inclusive) 

 before the close of that month (see Table XV) will be reached. And 

 after the close of Tzec, 13 uinals and the xma kaba kin must pass 

 before the end of the year; 13x20 + 5 = 265, and 265 + 12 = 277. 

 This latter number subtracted from 324, the total number of posi- 

 tions to be counted forward, will give the number of positions which 

 remain to be counted in the next year following: 324 — 277=47. 

 Counting forward 47 in the new year, we find that it will use up the 

 months Pop and Uo (20 + 20 = 40) and extend 7 positions into the 

 month Zip, or to 6 Zip. Therefore, gathering together the values 

 determined for the several parts of the terminal date, we may say 

 that in counting forward 5,799 from the starting point 2 Kan 7 Tzec, 

 the terminal date reached will be 3 Akbal 6 Zip. 



For the next example let us select a much higher number, say 



322,920, which we will assume is to be counted forward from the 



starting point 13 Ik Zip, Since this number is above 18,980, we 



may apply our preliminary rule (p. 143) and deduct all the Calendar 



43508°— Bull. 57—15 10 



