Ilustration. pies 
a _.| Factors or {Products or | | - 
No.| Courses. Dist.|Dif. lat} Dep. |multipliers.| areas. _ ec 
1.|S. EAB. E./AB pee a 2AEB) 
pas AEE ae cD] atte Boca 2BEKC! — 
3.|N.GC wD Zep) i RAL 
 4.IN. HAD. E DA'— pete oH HD 2DHA 
2\2ABCKLD 
3 ABCKLD=ABCD 
. the triangles DLM and MKC being equal.* 
The first meridian NS 
passes through the first sta- 
tion A. EB, DGand KC 
are drawn perpendicular 
to, and FC parallel with » 
NS. 
tors or|Products or 
areas. 
i : Dist. 
: Courses. chs. | pie. lat.| Dep. 
9.00; 4.50 7.79 7.79} 35,0550 
: ( 7 10.99! 71.9845 
2 -|14.00|—4-79| — 13.10] — 6.76 32.9804 
:.111.76|— 6.26] 9.96]— 9.96) 62.3496 
. “as 22087695 : 
-10.088475 aers. 
Iti is stated in the article alluded to, that “in the common method 
of computing the area of a field, a meridian line is supposed to be 
drawn ‘at some assumed distance from the commencing corner.” 
This it is imagined i is incorrect. ‘The most ‘‘*common mode,” is to 
select for the point of commencement, the extreme East or West 
station of the field. Through this station, the first meridian is made 
to pass, and the necessity of an “ assumed dusk” is thereby avoid- 
*DL=KC by construction. 
