SULL ATTRITO INTERNO NEI LIQUIDI 



215 



Soluzione ii" 2 - HNO' 72,85",; P.s.=:: 1,457 a 0" 



P 



P 



T 



0° 46.2 867" .0 0.00003348 16".82 46.05 557" .7 0.00002138 



0" 

 0" 



46.2 

 46.22 



864" .5 

 8 63'.1 



3339, 16''.82 46.30 557" .21 



3335 



16^82 46.30 554" .41 



2148 

 2138 



medio v:= 0.00003341 j 16°.82 medio •/; = . 000021405 



Donde si calcola fra 0" e 17° 



0.03276 



'^>i 



1+0.03338^ 



Soluzione n" 3 - HNO^ 71,24 ^ P. s. = 1,450 a 0" 



0.00003358 

 3356' 

 3344 



r 



P 



ri 



16°.87 46.16 560" .6 0.00002158 



16°.87 46.41I556" .2 2153 



16".88 46.86 552" .0 2157 



medio rr^O. 00002151 



Quindi si calcola fra 0° e 17° 



■/;,: 



0.03288 

 1+0.03337?' 



