330 W. Gibbs and F. A. Genth 
f: P= TOT 10’. 
I : ti = 148° 50’. 
O: i= 114° 15’. 
Twin crystals are frequent, the composition being parallel to 
the plane 0." The salt is very slightly soluble in cold water, but : 
dissolves in much boiling water, from which it separates on cool- 
ing. When gently heated in a porcelain crucible it gives off 
ammonia and chlorid of ammonium, and becomes green. 1he 
green mass, on solution in water, gives globular aggregations of 
minute crystals of a buff color, which may be a new salt, but 
which we have not specially examined. Zine decomposes the 
chlorplatinate of Luteocobalt only by very long boiling in an 
acid solution, metallic platinum being separated as a black pow- 
der, while chlorids of cobalt and ammonium are formed. 
The formula of the orange salt is 
6NH3.Co2Cls+3PtCla+6HO 
as the following analyses show: 
1°220 grs. gave 04321 grs, metallic platinum == 35-41 per cent, 
1-220 grs. gave 02261 grs, sulphate of cobalt = 7-05 per cent cobalt. 
Eqs. Calculated. Found. 
Cobalt, - - 2 7-10 0. 
Platinum, -- ~ - <2 85°64 - 85°41 
The formula of the yellow salt is 
NHs.Coz2Cls+3PtCls+21HO 
as appears from the analyses: 
0°2638 grs. gave 00822 grs. metallic platinum = 31°16 per cent. 
04449 grs. gave 06037 grs. chlorid of silver == 33-54 per cent chlorine. 
Eqs. Calculated. Found. 
Platinum, - 3 30°99 8116 
Chlorine, = - 2:9 33°42 33°54 
Rogojski f 7h. 
water, but his analyses are not very satisfactory, giving 
excess of platinum, hydrogen, and cobalt. 
. CHLORAURATE OF LUTEOCOBALT. 
- A solution of terchlorid of gold produces immediately: 
of the chlorid of Luteocobalt a beautiful yellow 
ski found in this salt but one and a half equivalents of 
a large 
in $0- 
