60 



QUELQUES REMARQUES SUR LA SOLUTION 



1..2 



P3 = 2 X 1 + (n — 4) (m _ 5) = 2x1+4x3 

 1...2 



P, = 3 X 2 + (?i — 5) {n — 6) 

 1....2 



3x2+3x2 



P. = 4 x 3 + {n — G) (71 — 7) = 4x3 + 2x1 



P„ r= 5 X 4 = (n — 7) in 

 1 ... . 



+5x4+1x0 



P7 = 6 x 5 + {n — 8) (m — 9) = 6 X 5 + X — 1 



