124 A NEW METHOD OF DETERMINING 
and, for ua? =) 
3 (1) 3 
iz NV 3bcos2Q, $8, = 7,wN 3bsin2Q. 
We divide by 8 to save division after quadrature. 
() (2) @) 
With these values of c,, s,, and the values of the coefficients 6,, we find the 
7 z 
7 
7 Uy 
values of k,, ;, from 
3 (7) (0) (i-1) (+1), (1) 
k, cos K; = 0, ¢, + (6 + 5b, \e 
Dy 
TN 
z B 
(=i )) (+41), (1) 
bs ) 
For 7 = 0, we find /) from 
, (0) (0) (it) CY) 
ko — 3 Dr Cn b,, Cn 
2 2 my 
. a 
Then in ease of tu (“) from 
A,, = }m'sk,cos [1(Q—gq)—4\] 
A,, = tm'sk,sin [0 (Q—g)—&A,], 
where m/’ is the mass of the disturbing body and s = 206264.’8 ; 
and from 
A,, = 3m sak, cos [i (QY— g) — Ki] 
A,, = tm soek,sin [¢(Q—g)— A], 
(a) 
: 3 (c) (s) z Zs 
in case of uwa> ( “) , we find the values of A,, and A,, for the 16 different points of the 
circumference, and the various terms of the series. 
