156 A NEW METHOD OF DETERMINING 
3 : : 0 : dQ 
Having a© we differentiate relative to g, and obtain a—. 
ag 
ig 
We then form the three products, A. a Bar =). Oxa: =. To this end 
we find A, B, C, from 
A = —3 = 22 = cos (7 — g) 
+215 + €] eos (7 29) 
— 2 [BS + 282] cos y 
+ 2£ cos (y--39) 
+ 2 cos (y —4g9) 
+- ete. 
dr 
B=—2— sein — 9) 
—2 [$+ 3] sin (y—29) 
— 2[5 + qee"] siny 
— 236 sin (y — 3g) 
— 2¢sin (y— 4g) 
— ete. 
C= 2[f—e] sn(y— 9) 
+ 2 [$—75e'] sin (y — 29) 
+ 2[—#e+ 46] sin y 
+ 23 
+ 2 te 
+ ete. 
sin (y — 39) 
sin (y — 49) 
The numerical values of A, B, C in case of Althza are 
A=—38 
+ 2 [0.802429] cos (y — g) 
+ 2 [8.604489] cos (vy — 29) 
. — 2 [9.304508] cos v 
+ 2 [7.2076] 
cos (y — 89) 
B = —2 [0.001399] sin (y — g) 
— 2 [8.604489] sin (y — 29) 
— 2, [8.606234] sin y 
— 2 [7.3836] sin (vy — 89) 
C = + 2[9.697567] sin (y — g) 
+ 2 [8.80066] 
sin (y — 29) 
— 2[8.77953] sin y 
+ 2['7.08265] 
sin (y — 39) 
