158 
A NEW METHOD OF DETERMINING 
Ala) /55 ar(S) C. aS) 
dg dr dz 
Me Ol OF sin cos sin COs sin cos 
ih dW ih II iA VW 
1 Weed == J1G5 = ahd == 1038 JE ls 
1 Oe 4 — 2,929 ae TY + 264 + 989 == 389 +1.029 
= ee eee aL Oil +. Oli oe. rr 2008 + .014 
ie eee —929.032 1.564 —15.481 + .915 L 022 33 
—1 3—4 JL 058 ==, IR = 039) + 175 5 {pA + .051 
1 4—4 — 1.0638 — 287 — 1.504 = (0S) — .140 — .3800 
ied — 4 + 1,268 — 024 022 2938 L .390 —1.033 
i he —28.751 +1.597 +15.479 = 5 | .033 9 
=| G4! — 4,543 — .108 + 1.506 + .098 
i B= 5 = 180 =5 156 L .002 + 088 
ily ey ees — 1.654 a 132 ==" 1063 + .063 — .206 26 Bi) 
78225 4. Oe + 014 = {001 — .008 _ 001 ae00S 
i 235 —16.185 JL 08 == 8.66! + 1544 | 034 + .038 
—l 4—65 + 015 — .148 — 045 36 8 — .035 + .004 
il B= 6 == IOI = .153 = IL — .036 == (0 = n68 
—l 5—5 —E 294 — .017 + 062 — .063 | 206 = G3 
—l 6—5 —16.0388 +1,100 + 8.661 — .b44 
i 86 = im = 08 
Teer een — 1.088 aL 083 | + 9.052 + .088 
1 5—6 = BOL aL 08 == Aol6 —- 387 
= NT 226 == 8818 ae pul + 4.516 == 38K 
Next from 2 
dw 
we find the value of ——. 
ndt 
OW = 4. a(“) + B.ar (=) 
nat dq Ta 
Then we find W and —“. from 
Cost 
