160 A NEW METHOD OF DETERMINING 
ae W = 
ndt cosz 
: | 
vy OF of sin cos | cos sin | cos sin 
7 ” an yy 7 Sale " ” 
1 O=@ 2. BPRG 1S |) == Wei 26 BOR pi | SONS; — IAAL ia! 
1 1—0 + .38901 + .9373. —  .3901 ak 9857/33 == 1287 + .2411 
1 1 0 32.6972 —- .0988 — 32.6972 + .0988 | SL BIST T — .4802° 
1 Y— (() —~—s-—« 20738 = 4647 — 6.1036 + .23823 | + .0024 + .0114 
=i 90 4 OAS =k OSL = A OS AE. LASS 
—l 3 — 0 + .13850 + .0850 —  .0450 + .0283 — .028 + 0801 
Te) eal 4. O04 == W167 BSB aL Oy — .033 = ld 
1—1—1 + 187 + .446 + .115 — .330 —0.62 — 1.60 
nee, es = 307 sb B40 — 83.900 = oe +1.013 + 1.84 
—l 0—1 — 015. + .530 —  .045 — 1.516 — .652 — 1.64 
1 1—1 + 4.609 —1.374 — 1.087 — 2.112 - +1.264 — 2.74 
ie Seibel Lo Bn = AS) — 1.030 — 5D —1.370 —= R21 
1 4 —— Il — 036) = 153 + 022 + .45 — .040 + .06 
—l 2—1 aE OR) SE OGL — 4,263 + .038 | a KO § — 21 
eee al = OG) Se LOOT JE 9B | 
=I) Bi “LAB = O84 == 4) = Oy = 26 + .670 
Teas al oT a als J OBL 4 029) 
1—1— 2 — .03 — .ll 
1 0—Q + 14.145 + .261 + 20.207 = oie —1.76 — 4.33 
1 o¥ 12ALG ALBIN) +419.660 +11.503 59 — 128 
he PBS) 116 + .408 + 2,380 + 1.356 + .46 + .96 
1 2— 2 -—— 1.8387 —1.119 + 1.410 — .860 ++ .36 — .78 
—Il 2—2 + 9116 — .475 — 17.008 — .365 — .95 — 2.34 
la 8.2289 Ho AS — 204 42 = He Oil 
<1 §—9 — 33.666 -+ .990 ++ 14.632 + .430 == 02 = 19 
1 te59 = Ole = 1% SE D5 SE 033 
Se vee) — 8150 = 1G + 9.469 — .035 — 4 4. 20 
= 9 = PIO se 4099 e050 4 {pH 
1 O08 J- 1009 = 4914 | - 10ie6 +. A501 == .05 Seals 
1 ls 3} — 1.5475 -—- .3568 — 31.8180 — 1.335 —14.56 — 371,33 
=I ils = (012 + 0893 | = O52 = Lear 4. D5 = BY 
ae = 78 — 77.4394 +9.9904 | + 81.400 + 3.139 = 0 == 318 
1 2 3 EL 2Ory Se ee —  .3124 + 1631 + .06 + .14 
Te 338 = 397G4 — jel | = ier9 = BB5 1 183 = 28 
=—l 8—=8 | + 98708 = 235 | — 1916 = 192 = 28 = ol 
1 Gea B | sk Avis se Bey = 050 a ealiity .00 .00 
=| 48 = OA, +. $98 | — 74g JL SS = OI = 
Sl 5-58 Seo 196 ee 047 a eo = 12 = 08 ae 8 
ih Shas = Ge } = Ane = 008 = 2 
i Q—4 — 1.96537 41.126 | + 3.265 + 1.871 ae 64 (eae ole 
ae = Wiis LO | aL BILTOD + 1.548 = 0 = 
=—1 8-4 = 81 = 12 SO = 00" 4 O15 + 08 
1 he = W5G7 = £5 + 986 = 149 J BA =D) 
=i 44 ae 002) == 7963 == Ba = Bi = 150 = 
to esd = (PQ sb soy SAO G + .016 
—l 5+4 = 1B Ae 832 + 3.686 + .190 = 00 — 
=i G4 == ROBT — {00 + 660 = 2 
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