344 REPORT—1896. 
the benzene solution. The results of the analysis of this substance most 
nearly accord with a formula C,,H,,Cl,Oo. 
(a) 0-420 gram gave 0°740 gram CO, and 0-114 gram H,0. 
0:463. 4, » 0451 ,, AgCl=24-05 per cent. Cl. 
(b) 0386 ,, » 90680 ,, CO, and 0:104 gram H,0. 
0:569 _,, » 0:550 ,, AgCl=23-°88 per cent. Cl. 
Calculated for 
a b C484 3C1,0, 
C; 48-05 é : 48 05 ; 4 48-66 
i. dUL 5 2 2°99 ° : : 3°04 
Cl. 24:05 - ‘ 23°88 ° c . 23°96 
O. 24°89 : : 25:08 9 : , 24:34 
100:00 
From the material left after extraction with benzene and alcohol, 
which is sparingly soluble in hot alcohol but soluble in acetone, two sub- 
stances have been obtained which contain a smaller proportion of chlorine 
than the above, and from the analytical results appear to have the formule 
C,.H,,Cl,0; and C,;H,,Cl,0,. The deep yellow acid filtrate from which 
the oxidised and unoxidised coal had been removed was shaken out with 
ether ; the ethereal solution appears to contain some trichloracetic acid. 
The aqueous solution, after extraction with ether when concentrated to a 
small bulk, deposits crystals of potassium chloride, &c., coloured yellow by 
a colouring matter which is removed by acetone. The acetone solution, 
on evaporation, gives a reddish viscous liquid, which is dissolved by ether 
and alcohol, but is insoluble in benzene. 
The analysis of the residue left after the evaporation of acetone 
showed that it contained some mineral matter, which was left as ash when 
the substance was burnt. Owing to the small amount at disposal, a 
further purification was not attempted. The determination of the carbon, 
hydrogen, and chlorine gave the following :— 
(a) 0°4132 gram gave 0°6460 gram CO, and 0:1414 gram H.0. 
0°4158 _,, » 02584 ,, AgCl=15-36 per cent. Cl. 
(0) OBON fins » 9°5608 ,, CO, and 0:125 gram H,0. 
04402 _,, 9» 02706 ,, AgCl=15-:20 per cent. Cl. 
0-426 =, » O01D 4s. <Ash=35'52 per cent. 
a b 
C. 42°61 per cent. - 42°82 per cent. 
Tel D200. ees, : 3°88 4: 
Cl. 15°36, E 15°20 4 
Ash _- — 3°52 per cent. 
Calculating the percentage of carbon, hydrogen, chlorine for the sub- 
stance free from ash, we get amounts corresponding to the formula 
C33;H;,Cl,0,5, as shown below :— 
Calculated for 
a b C33 H56Cl4O29 
C. = 44:18 44:39 44°29 
Ee 304: 4-03 4:02 
Olea 15-76 15°88 
O. = 35:96 35°82 35°81 
