272 Prof . Latham, On the formation of lactic acid, [May 11, 



By condensation of the aldehyde glucose is formed 



6H . CHO = C 6 H 12 6 



aldehyde glucose 



which by dehydration is converted into starch 



C 6 H 12 6 = C 6 H lb 5 + H 2 



glucose starch 



In muscular tissue now, by hydration of CH 2 \p^r we form 



glycollic acid, which when oxidised in the tissue is converted into 

 methyl aldehyde, and this by condensation produces glucose, which 

 by dehydration gives rise to glycogen ; 



OH ! {0= + 2H,0 = OH,^ OII =NH, 



methene glycollic acid 



cyan-alcohol 



CH 2 {£ J 0H + O = H . CHO + C0 2 + H 2 



glycollic acid methyl 



aldehyde 



6H.CHO = C 6 H 12 6 



aldehyde glucose 



and C 6 H 22 O 6 = C e H 10 O 5 + H 2 O 



glucose glycogen. 



From what I have said as to the formation of urea in muscular 

 tissue it is easy to understand why, when leucine or glycocine are 

 introduced into the alimentary canal, a proportionate quantity of 

 urea appears in the urine*. Taking glycocine for example, two 

 molecules in passing from the alimentary canal to the liver are 

 dehydrated 



2CH 4c?OH - pttI^- 011 



UJi 3 \COOH 



This now is attached to the last molecule in the albuminous 



iOTT 

 p^- and we have 



chJ &c. \ 



^CN . OH + ^CN . OH 



CH 2 CH 2 



l COOH l CN 



* Foster's Physiology, 4th ed., p. 439. 



