230 
Therefore on eliminating 4, 
AS .Sina.@ = sina. 
+e r =42seea.cos (sinacosa.”.y). 
: : 1 
Tn the second case, that is, when p is less than 5 ov", assume 
: 2p 
aoe 
sin? B= oo? 
(5 d.tan gd _ tan 8 lo tan 8 +tangd 
nt cotae tau G2), 3° tan B~ tang 
_tan@ sin (8+ ¢) . 
~ -log. (a=) (CEE 
Be Se [eee cos .dd Lsiay8 lo sin 8+sin 
—cosec’B8.sinr®?d 2 ° °'sinB~sind 
then 
Pp B y= = Su db -{. d.cos 
cosec? 8. sin? osec” 8 . cos” d — cot’ B 
Sua d.cosd sin? 8B cos ¢ + cos B 
= an ef sec’ 8. cos" d ~ 2 cos B’ 1Og * as CTS 
_ Sint B Seam appee Sioa 
= Jeong: los: (cot 5 . cot 5 ip 
after eliminating @, the rectangular equation is found to be 
cosB p 1p cosB p,, 1 Pp 
+ e sin? 7” Bsineiccee +e sin?B° 7” sinB’r*” 
tan 8B == 
2cos B p 
+e sin’s * or fee 
Tn the case when p a5 ov 
P 2 = p 
== sec ddé=tand, e7 +e7 = 427 -y- 
