LAKES OF THE LAHONTAN BASIN. 



77 



Pit cent. 



Soda 40. 55 



Carbonic acid 36. 86 



Sulphuric acid 0. 73 



Cblorine 0. 98 



Water 19. 90 



Insoluble residue . . . 0. 80 



99. 82 

 Oxygen equivalent to chlorine 0.2Q 



99.60 



"The deposit is thus nearly a pure trona, or sesquicarbonate of soda, 

 mixed with small quantities of" sulphate of soda and common salt It con- 

 tains also traces of phosphoric and boracic acids. The insoluble residue 

 consists of fine sand and carbonate of lime." 



Samples of water collected in September, 1882, in the central portion 

 of the lake, at the depths of 1 foot and 100 feet, have been analyzed by Dr. 

 T. M. Chatard, who reports their composition as follows: 



One liter of wa- 

 ter contains in 

 grammes— 



Constituenta. 



Silica (SiOj) 



Magnesium (Mg) 



Potassium (K) 



Sodinm (Na) 



Chlorine (01) 



Sulpburic acid (SO4) ■ 

 Boracic acid (B4O7) . - 



Carbonic acid (CO3) by difference. 

 Total 



CO 



a o S 

 C.O^ 



0.3U4 

 0.270 

 2.520 

 45. 840 

 45. 690 

 12. 900 

 0.314 



107. 898 

 17. 232 



ii 



a 4>,« 



Per cent, in total 

 solids. 



0.310 

 0.270 

 2.670 

 44. 270 

 44. 270 

 13. 150 

 0,327 



lO.i. 267 

 19.883 



a « 



'i^ o 



0.24 

 0.22 

 2.01 

 36.63 

 36.51 

 10.36 

 0.25 



a k 



|l 



a ® o 



0.25 

 0.21 

 2.13 

 35.38 

 35.38 

 10.50 

 0.26 



84.11 

 15.89 



100. 00 100. 00 



ConetitBents. 



Silica (SiOs) 



Magnesium carbonate (MgCOa) 



Potassium chloride (KCl) 



Sodium chloride (NaCl) 



Sodinm sulphate { N'a2S04) 



Sodium borate (NaaBaO?) 



Sodium carbonate (Na'iCOa) . . . 



Probable combi- 

 nation (expressed 

 in grammes per 

 liter). 



Loss* 



Total . 



s fe 



a o o 

 B.o a 



0.304 

 0.940 

 4.820 

 71. 470 

 19. 170 

 0.404 

 26.410 



1-2 



n <& ^ 





-.££ 



0.310 

 0.940 

 5.110 

 68. 930 

 19. 450 

 0.417 

 24. 840 



119. 997 



{5. 153 



126. lao 125.150 



123.518 

 f 1.612 



* If the excess of CO3 above the amount required for NajCOs be calculated as NaHCOs, we will have in the sample 

 from 1 foot below the surface: 123.518 less Na^JOs = 97.108 



HaiCOa = 23.64 

 KaHCOj = 4.382 



12.5.130 



and in the remaining sample; 119.997 less NaiCOs = 95.157 



NaCOa = 16.04 

 NaHC03= 13.953 



1 98.71 per cent, accounted for. 

 i 95.98 per cent, accounted for. 



